Ande Yashwanth
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Find derivative of y=✓{x+✓[y+✓(x+...)]}infinite.
Here root comes for total inter terms
Here root comes for total inter terms
y= \sqrt{x+ \sqrt{y+ \sqrt{x+ \cdot\cdot\cdot}}} is clearly the same as y= \sqrt{x+ \sqrt{y+ y}}= \sqrt{x+ \sqrt{2y}}.Ande Yashwanth said:Find derivative of y=✓{x+✓[y+✓(x+...)]}infinite.
Here root comes for total inter terms