Diffraction - Calculating Width of a Slit

Click For Summary

Homework Help Overview

The original poster is tasked with calculating the width of a single slit in a diffraction experiment. They have a known distance between the observation screen and the slit, along with photo images of the resulting waveform, but lack the wavelength of the light used, complicating their ability to apply relevant equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster expresses uncertainty about which equations or theories to apply due to the unknown wavelength. They mention using Pythagoras to find distances related to the fringes. Participants question whether the wavelength might have been provided indirectly and suggest checking the color of the light used in the experiment.

Discussion Status

Participants have offered guidance regarding the potential wavelength of red light from a helium neon laser, suggesting that the original poster could look up this value for further calculations. There is an ongoing exploration of the information available from the experiment and the implications of using an approximate wavelength.

Contextual Notes

The original poster's problem is constrained by the lack of explicit information regarding the wavelength, which is critical for their calculations. The discussion also highlights the importance of thoroughly understanding the experimental setup to avoid missing data.

MRL
Messages
7
Reaction score
0

Homework Statement


I am required to calculate the width of a single slit. I have known distance, L, between the observation screen and the slit, and photo images were taken of the resulting waveform. However, the wavelength is unknown, therefore making many of the equations I'm attempting to use void.


Homework Equations


asinθ = mλ ; for a dark fringe, were a is the slit width, λ is the wavelength, and m is the order of the minimum. However, as in my case both λ and a are unknown, this cannot be used.


The Attempt at a Solution


I'm usure as to what equations/theory i can use, although i know i can use pythagoras to find the distance between a fringe and the slit, using L and the distance of fringes from the centre of the screen.

Thanks.
 
Physics news on Phys.org


Hi MRL.Are you sure that the wavelength was not given,perhaps in a different part of the question or indirectly? Since you were given a photo image I'm assuming visible light was used so did the photo show what colour was used?If so you can look up the wavelength.If the photo was black and white you could give an approximate value for the wavelength eg the wavelength for yellow.
 


Dadface said:
Hi MRL.Are you sure that the wavelength was not given,perhaps in a different part of the question or indirectly? Since you were given a photo image I'm assuming visible light was used so did the photo show what colour was used?If so you can look up the wavelength.If the photo was black and white you could give an approximate value for the wavelength eg the wavelength for yellow.
Thanks for the reply. It was practical experiment that i did, and we were required to take photos of the results. A red laser was used, so would you suggest i use the wavelength for red light?
 


Yes,use the wavelength for red.I'm guessing it was a helium neon laser so you might want to google to get a more precise value for the wavelength.
 


Dadface said:
Yes,use the wavelength for red.I'm guessing it was a helium neon laser so you might want to google to get a more precise value for the wavelength.
OK, thanks for your help.
 


Dadface said:
Yes,use the wavelength for red.I'm guessing it was a helium neon laser so you might want to google to get a more precise value for the wavelength.
I second this tip. :smile: However...
It's always good to understand well the lab before proceeding. You could avoid to miss data (that aren't necessarily on the Internet).
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
6
Views
3K