Diffraction grating angular separation

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The discussion focuses on deriving the angular separation of two wavelengths incident on a diffraction grating. The equation D sin(Theta) = mL is used to relate the angles and wavelengths. An initial attempt to find dTheta resulted in an incorrect expression. The correct formula for angular separation is dTheta = dL / ((D/m)² + L²)^(0.5). The importance of using small angle approximations for sin(Theta) is emphasized to achieve the correct result.
charlesh
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Homework Statement


Light consisting of two nearly equal wavelengths L and L+dL, where dL << L, is incident on a diffraction grating. The slit separation of the grating is D. Show that the angular separation of these two wavelengths in the m'th order is dTheta = dL / ((D/m)2+L2)0.5


Homework Equations



D sin(Theta) = mL (m=0,+-1, +-2,...)

The Attempt at a Solution



D sin(Theta1)=m(L+dL)
D sin(Theta2)=m(L)
dTheta = sin(Theta1)-sin(Theta2) = (m/D)(L+dL-L) = (m/D)dL= dL/(D/m)
This answer doesn't match the formula I need to proof: dTheta = dL / ((D/m)2+L2)0.5
 
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charlesh said:

Homework Statement


Light consisting of two nearly equal wavelengths L and L+dL, where dL << L, is incident on a diffraction grating. The slit separation of the grating is D. Show that the angular separation of these two wavelengths in the m'th order is dTheta = dL / ((D/m)2+L2)0.5


Homework Equations



D sin(Theta) = mL (m=0,+-1, +-2,...)

The Attempt at a Solution



D sin(Theta1)=m(L+dL)
D sin(Theta2)=m(L)
dTheta = sin(Theta1)-sin(Theta2) = (m/D)(L+dL-L) = (m/D)dL= dL/(D/m)
This answer doesn't match the formula I need to proof: dTheta = dL / ((D/m)2+L2)0.5

highlighted part is incorrect
 
Thanks for the response.
For small angle, sin(Theta) is very close to Theta (in radian).
 
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