Diffraction Grating, Maxima, finding slit seperation

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Light with a wavelength of 680 nm is incident on a diffraction grating, producing adjacent maxima at angles where sin θ = 0.2 and sin θ = 0.3. The fourth-order maxima are absent, indicating that the conditions for diffraction orders must be carefully analyzed. The relationship between slit width and angle can be derived from diffraction equations, confirming that the orders are indeed 2 and 3. The minimum slit width can be determined by ensuring that the sine of the angle for the fourth order exceeds 1, which confirms the absence of the fourth maximum. Accurate calculations and attention to rounding are essential for determining the correct slit width.
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Homework Statement


Light of wavelength 680 nm is incident normally on a diffraction grating. Two adjacent maxima occur at angles given by sin θ = 0.2 and sin θ = 0.3, respectively. The fourth-order maxima are missing.

(b) What is the smallest slit width this grating can have?

Homework Equations

The Attempt at a Solution


What equations relate slit width to angle theta?
 
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The diffraction orders do not have to be 1 and 2. Actually they are not.
You don't need to assume their values. The information that the maxima are adjacent is enough. With your notation, that means m2=m1+1.
You can find both d and m1,m2 from the equations (with the above condition).
 
Yes, I had tried that, but it gave me values that I thought were too far from the correct answer (which I knew the value of). I've looked at all the numbers more closely, and it's just rounding preferences, is all the matter.

Thanks.
 
I edited the first post, to make it about the second part of the problem, for which I cannot think of any equations.
 
There is nothing about rounding. The diffraction orders are 1 and 2 (in the first part).
The same equation will give the minimum size of the slit. The condition is that you have only the maxima with orders 0 to 3 and nothing at 4.
That means that the sin(theta) will have to be l>= 1 for order 4.
 
There is nothing about rounding. The diffraction orders are 2 and 3 (in the first part).
The same equation will give the minimum size of the slit. The condition is that you have only the maxima with orders 0 to 3 and nothing at 4.
That means that the sin(theta) will have to be l>= 1 for order 4.
 
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