Diffraction of Light through Single Slit

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The problem involves calculating the wavelength of monochromatic light passing through a slit of width 3.00 x 10^-6 m, with the angle between the first dark fringes at 25 degrees. The correct interpretation of the angle is crucial, as it should be measured from the central maximum, not between the fringes. The equation sin(θ) = nλ/w is applied, where θ represents the angle to the first dark fringe. The initial calculation yielded an incorrect wavelength of 1.3 x 10^-6 m, while the correct answer is 6.49 x 10^-7 m. Understanding the proper use of the angle in the equation is essential for solving the problem accurately.
samdiah
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Homework Statement



Monochromatic light falls into slit 3.00*10^-6 wide. The angle between the first dark fringes on either side of the cental maximum is 25 derees. Calculate the λ.

w=3.00*10^-6 m
ө=25˚

Homework Equations



sin(ө) = nλ/w
sin(ө) = ((m+0.5)λ)/w
Δy=λL/w

The Attempt at a Solution



sinө=λ/w
λ=sin25*3.0*10^-6
=1.3*10^-6 m

hoever the answer is 6.49*10^-7
 
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Please help its really easy I just don't get the concept!
 
samdiah said:
The angle between the first dark fringes on either side of the cental maximum is 25 derees.
You have misinterpreted the angle. You are given the angle between the first dark fringes, but in the equation sin(theta) = n lambda/w, theta is the angle of the dark fringes measured from the central maximum.
 
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