Diffusion equation without initial conditions

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SUMMARY

The discussion focuses on solving the one-dimensional diffusion equation represented by the formula u_t = ku_{xx} with specific boundary conditions: u(0,t) = T_0 + A cos(wt) and u(x→∞,t) → T_0. Participants clarify the interpretation of time and space variables, emphasizing that time should be non-negative. A suggested approach includes using the method of separation of variables, specifically U(x,t) = X(x)T(t), to derive a solution.

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davidnr
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Hi,
How can I solve the diffusion equation in one dimension:
[tex]u_t=ku_{xx} ; -\infty < t < \infty , 0<x<\infty[/tex]
With the boundary conditions:
u(0,t)= T_0 +Acos(wt)
[tex]u(x\rightarrow \infty,t) \rightarrow T_0[/tex]
Thanks!
 
Last edited:
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davidnr said:
Hi,
How can I solve the diffusion equation in one dimension:
[tex]u_t=ku_{xx} ; -\infty < t < \infty , 0<x<\infty[/tex]
With the boundary conditions:
u(0,t)= T_0 +Acos(wt)
[tex]u(x\rightarrow \infty,t) \rightarrow T_0[/tex]
Thanks!
Does one maean -
[tex]-\infty < x < \infty , 0< t <\infty[/tex]
I'm not sure t < 0 makes sense, unless it's a relative time.

At some large distance, T = To.

Try using U(x,t) = X(x)*T(t).
 
You might add a constant to Astronuc's trial solution.
 

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