Diffusion Ques: Unintuitive Concentration Change Over Time?

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Homework Help Overview

The discussion revolves around the behavior of gas particle concentration in a box, particularly in relation to the diffusion equation and its implications over time. Participants explore the conditions under which concentration remains constant or changes, focusing on a linear distribution in one dimension and uniform distribution in others.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants examine the diffusion equation and its predictions regarding concentration changes over time. They discuss specific initial conditions and boundary conditions, questioning the implications of these setups on the concentration profile.

Discussion Status

The conversation is active, with participants sharing mathematical reasoning and interpretations of the diffusion equation. Some guidance has been offered regarding boundary conditions and their effects on the concentration profile, although there is no explicit consensus on the implications of the findings yet.

Contextual Notes

Participants are considering specific initial and boundary conditions, including impermeable boundaries and the maintenance of a linear concentration profile. There is an underlying assumption regarding the behavior of the diffusing species that is being questioned.

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If the gas particles in a box are uniformly distributed in the y and z directions, and linearly distributed in the x direction, is it true that the concentration won't change with time, according to the diffusion equation? I find this very unintuitive.
 
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Me too. Can you go through the steps to show why you think the diffusion equation predicts that?
 
[tex] \frac{dc}{dt} = D \frac{d^2c}{dx^2}[/tex].

If c(x,0) = 2-x, then

[tex] \frac{d^2c}{dx^2}=0[/tex]

and consequently

[tex] \frac{dc}{dt}=0[/tex]

That is, the concentration does not change with time.
 
Setting

[tex]\frac{\partial^2c}{\partial x^2}=0[/tex]

for nonzero times means that you're replacing diffusing particles with new particles to keep [itex]c=2[/itex] at [itex]x=0[/itex], and you're removing all the particles at [itex]x=2[/itex] to keep [itex]c=0[/itex]. In other words, you're maintaining the linear relationship.

For a constant amount of the diffusing species, try solving the equation for the boundary conditions

[tex]c(x,0)=2-x[/tex]

[tex]\frac{\partial c(0,t)}{\partial x}=\frac{\partial c(2,t)}{\partial x}=0[/tex]

which implies impermeable boundaries. You'll find that at long times the solution approaches [itex]c=1[/itex] everywhere. Make sense?
 

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