Dimensional Analysis of Planck Length

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SUMMARY

The discussion centers on the dimensional analysis of the Planck length, defined by the equation l_p = √(Għ/c^3). Participants identified errors in the dimensional analysis of the constants involved, specifically the dimensions of Planck's constant (ħ) and Newton (N). The correct dimensional representation of Planck's constant is joule-seconds (J·s), which translates to m²·kg⁻¹·s⁻¹. Proper conversion of Newton to its base SI units is essential for accurate calculations.

PREREQUISITES
  • Understanding of dimensional analysis in physics
  • Familiarity with fundamental constants: Gravitational constant (G), reduced Planck's constant (ħ), and speed of light (c)
  • Knowledge of SI unit conversions, particularly for Newton (N)
  • Basic principles of black hole thermodynamics
NEXT STEPS
  • Study the derivation of the Planck length using the equation l_p = √(Għ/c^3)
  • Learn about the significance of Planck's constant in quantum mechanics
  • Explore dimensional analysis techniques in theoretical physics
  • Review the relationship between gravitational force and its representation in SI units
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Physicists, students of theoretical physics, and anyone interested in the fundamentals of quantum mechanics and gravitational theories.

noahcharris
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Hello!

So in looking at black hole thermodynamics, I came across the equation

## l_p = \sqrt{G\hbar} ##

But in doing a dimensional analysis of
## \sqrt{G\hbar} ##
I get

## [\sqrt{G \hbar}] = \sqrt{ \frac{Nm^2}{kg^2} \frac{m^3}{kgs} } ##

This obviously doesn't amount to a length. What am I doing wrong here?
 
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noahcharris said:
I get

## [\sqrt{G \hbar}] = \sqrt{ \frac{Nm^2}{kg^2} \frac{m^3}{kgs} } ##

This obviously doesn't amount to a length. What am I doing wrong here?

The Planck length is equal to
\sqrt { \frac {G \hbar} { c^3} }

You got the dimension of Plancks constant wrong. A joule second is not m^3/(kg.s)

You also need to convert Newton to kg, meter and second.
 

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