Dimensional analysis of the london penetration depth

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phja
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hi guys.

i have the london penetration depth defined as [tex]\lambda_l = \sqrt{\frac{m^{**}}{4\pi n_{s} e^{2}}}[/tex].

i'm trying to figure out the dimensionality of it...surely it must be a length, but i get

[tex][(Kg)(m^{3})(A^{-1}s^{-1})]^{0.5}[/tex]

in SI units.

am i doing something wrong?

cheers.
 
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There are some units set to '1' in this expression, which is why your analysis comes out funky. You will need some factors of c or [tex]\mu_0[/tex] in your expression for the depth to make the dimension come out correct.

You could try to re-derive the expression for the depth yourself (just google it), and use the expression for the Maxwell equation with the proper units in place. It's doable!