1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Superconductor coherence length and penetration depth

  1. Feb 22, 2014 #1
    1. The problem statement, all variables and given/known data
    I have a lot of information about 2 different superconductor materials; indium and lead. The indium is pretty much 100% indium with no impurities, and the lead is unknown purity.
    I have the temperatures and magnetic fields at which they are superconducting and the temperatures and magnetic fields at which they're in the transition between the superconducting state and the vortex state.

    What I need to do is calculate the coherence length and London penetration depth of both of these materials.


    2. Relevant equations
    The two equations I've found are...

    coherence length = [itex]\sqrt{\frac{\hbar^{2}}{2m|\alpha|}}[/itex]

    Where m is the mass of a cooper pair (2 times e), but I don't know what alpha is. Does it vary from material to material? How would I find out this value?

    And the london penetration depth = [itex]\sqrt{\frac{mc^{2}\epsilon}{ne^{2}}}[/itex]

    Where epsilon is epsilon naught, the permittivity of free space, and n is superconducting electron density.

    I also found another equation for london penetration depth.

    [tex](\frac{m}{q^{2}n\mu})^{\frac{1}{2}}[/tex]

    Where mu is mu naught, the permeability of free space.
    I'm not sure which of these equations to use.

    3. The attempt at a solution
    It looks like I can solve for the london penetration depth. I think I have all of that information. But for the coherence length, I need to know what alpha is. Anyone know?

    Thanks.
     
  2. jcsd
  3. Feb 22, 2014 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    The two formulas for the london penetration depth look equivalent, as q2=e2 and c can be expressed in terms of ##\epsilon_0## and ##\mu_0##.

    I don't know what α is.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Superconductor coherence length and penetration depth
Loading...