Dimensions of Eigenspaces of A | 6x6 Matrix Characteristic Equation

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SUMMARY

The discussion focuses on the dimensions of eigenspaces for a 6x6 matrix A with the characteristic equation (x^2)(x-1)(x-2)^3=0. The eigenvalues identified are x=0, x=1, and x=2. The possible dimensions of the eigenspaces are specified as follows: for x=0, the dimension can be 0, 1, or 2; for x=1, the dimension is 0 or 1; and for x=2, the dimension can range from 0 to 3. The relationship between the dimension of an eigenspace and the multiplicity of the eigenvalue is also emphasized, stating that 1 ≤ dim(E_{\lambda}) ≤ multiplicity(λ).

PREREQUISITES
  • Understanding of eigenvalues and eigenspaces
  • Familiarity with characteristic polynomials
  • Knowledge of matrix theory, specifically for 6x6 matrices
  • Concept of algebraic and geometric multiplicity
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  • Study the relationship between eigenvalues and eigenspaces in linear algebra
  • Learn about the algebraic and geometric multiplicity of eigenvalues
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Students and professionals in mathematics, particularly those studying linear algebra, matrix theory, and eigenvalue problems. This discussion is beneficial for anyone looking to deepen their understanding of eigenspaces and their dimensions in relation to characteristic equations.

georgeh
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So the question states:
Let A be a 6x6 matrix with characteristic equation (x^2)(x-1)(x-2)^3=0
What are the possible dimensions of eigenspaces of A?
so..
eigen values possible are
x=1,x=0,x=2
for x = 0
dimension 0?
for x = 1
I would say at dimension 0 or 1

x = 2
Dimension 0, 1, 2, 3
They have for x= 0
1 or 2
for x = 1
1 dimension
for x =2: 1,2,or 3
I am not sure how they got these answers. Any help would be appreciated.
 
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for a given eigenvalue \lambda, the dimension of the corresponding eigenspace E_{\lambda} must satisfy

1 \leq dim(E_{\lambda}) \leq multiplicity(\lambda)
 
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