- #36

#### SammyS

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Let's see now. That gives you: ##\displaystyle f_5=\begin{cases} x^2 & x \in [0,1]\\ x^3 & x \in [1,2 ]\\ \end{cases} \ ## and ##\displaystyle \ f_1=\begin{cases} x & x \in [0,1]\\x^3 & x \in [1,2]\\\end{cases}I can fix it by changing ##(0,0,0,0,1)## to ##(1,0,0,0,1)## thus converting ##f_5## to

$$

f_5 =

\begin{cases}

x^2 & x \in [0,1]\\

x^3 & x \in [1,2]\\

\end{cases}$$

##

So that ##\displaystyle f_5-f_1=\begin{cases} x^2-x & x \in [0,1]\\0 & x \in [1,2]\\\end{cases} ##