Dimensions of the pion decay constant

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Discussion Overview

The discussion revolves around the dimensional analysis of the pion decay constant \( f_{\pi} \) in the context of quantum field theory. Participants explore the normalization of single-particle states and the implications of delta functions on dimensional consistency.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the definition of the pion decay constant and notes a mismatch in dimensions between the left and right sides of the equation, questioning where the problem lies.
  • Another participant discusses the normalization of the single-particle state \( |\pi^+ \rangle \) and provides a standard definition, asserting that the dimensionality of the state is \( 1/\text{energy} \), which supports the dimensional correctness of the formula.
  • A later reply acknowledges the role of the delta function in dimensional analysis, indicating that it carries a dimension of -3, which resolves the initial concern about dimensional inconsistency.
  • Another participant reiterates the importance of considering the delta function's dimension and discusses the implications of the prefactor \( \sqrt{p^2 - m^2} \) on the dimensions of the states.

Areas of Agreement / Disagreement

Participants generally agree on the importance of the delta function's dimension in resolving the dimensional analysis issue, but there is no consensus on the broader implications or the exact values of the pion decay constant as it varies in literature.

Contextual Notes

There are unresolved aspects regarding the normalization conventions used in different sources, which may affect the interpretation of the pion decay constant's value.

anthony2005
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The pion decay constant f_{\pi} is defined by
<0|\overline{d}\gamma^{0}\gamma^{5}u|\pi^{+}>=f_{\pi}m_{\pi}
where I have set the momentum \boldsymbol{p}=0 (and used the temporal component of the axial vector).
Now, at the right-hand-side the dimension is two (the decay constant and the mass are measured in MeV). At the left-hand side, each quark carries dimension 3/2, so the whole axial vector has dimensions 3.
The dimensions do not match! Where is the problem?
 
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How is the single-particle state ##|\pi^+ \rangle## normalized? The standard definition is that
$$|\vec{p} \rangle = \hat{a}^{\dagger}(\vec{p})=|\Omega \rangle, \quad [\hat{a}(\vec{p}_1,\hat{a}^{\dagger}(\vec{p}_2)]=(2 \pi)^3 2 \sqrt{m^2+\vec{p}_1^2} \delta^{(3)}(\vec{p}-\vec{p}').$$
This implies that
$$\langle \vec{p}_1|\vec{p}_2 \rangle=(2 \pi)^3 2 \sqrt{m^2+\vec{p}_1^2} \delta^{(3)}(\vec{p}_1-\vec{p}_2),$$
i.e., ##|\vec{p} \rangle## as the dimension ##1/\text{energy}##, and thus your formula is dimensionally correct. You only should take care of the value of ##f_{\pi}##, which varies in the literature. Assuming that your source uses the same normalization of states your pion-decay constant is ##f_{\pi}=\sqrt{2} F_{\pi} \simeq 130 \; \text{MeV}##.

For a very nice review on chiral symmetry in QCD see

https://arxiv.org/abs/nucl-th/9706075
 
Thanks, that perfectly solved my problem. I wasn't thinking about the delta function carrying a dimension, but indeed if we think of <br /> \delta\left(\boldsymbol{p}\right)\propto\int d^{3}xe^{i\boldsymbol{p}\cdot\boldsymbol{x}} then the measure will lead to -3.
 
anthony2005 said:
Thanks, that perfectly solved my problem. I wasn't thinking about the delta function carrying a dimension, but indeed if we think of <br /> \delta\left(\boldsymbol{p}\right)\propto\int d^{3}xe^{i\boldsymbol{p}\cdot\boldsymbol{x}} then the measure will lead to -3.

##\delta^{(3)}(p)## has dimension -3 in post #2. The prefactor ##\sqrt{p^2 - m^2}## has dimension one, which leads to the states having dimension -1.
 
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