Diminishing Gravitational Acceleration with Distance

Click For Summary
SUMMARY

The gravitational acceleration diminishes with distance according to the equation g = GM/(R + h)^2, where G is the gravitational constant, M is the mass of the gravitating body, R is the radius of the body, and h is the height above the surface. The gravitational force follows an inverse square law, expressed as F = GMm/r^2, indicating that doubling the distance between two masses reduces the gravitational force by a factor of four. For accurate calculations when dealing with non-spherical objects or varying mass distributions, integration may be necessary. Newton's second law, F = ma, is also relevant for determining acceleration in this context.

PREREQUISITES
  • Understanding of gravitational constant (G)
  • Familiarity with Newton's laws of motion
  • Knowledge of inverse square laws
  • Basic calculus for integration
NEXT STEPS
  • Explore the derivation of gravitational force using calculus
  • Study the implications of the inverse square law in physics
  • Learn about integration techniques for non-spherical mass distributions
  • Investigate applications of gravitational acceleration in astrophysics
USEFUL FOR

Students of physics, astrophysicists, and anyone interested in understanding gravitational forces and their mathematical representations.

cbd1
Messages
123
Reaction score
1
I'm wondering what the equation is that shows how a gravitational field diminishes with distance from the object of mass. I would be looking for an equation showing the difference in the value of gravitational acceleration at points in space with increasing distance from the body. Would this be shown with a differential equation?
 
Physics news on Phys.org
[tex]g = \frac{GM}{(R + h)^2}[/tex]

Where G is the gravitational constant, M is the mass of the gravitating body (the Earth for example), R is the radius of the body (radius of the Earth for example), and h is the height above the surface of the body.
 
GMm
----- or (GMm)/r^2
r^2

is the formula for the gravitational force. G is the gravitational constant, M is the mass of one object, m is the mass of the other object and r is the distance between the two. r is measured from the center of mass of the both objects so my r equals Superstrings (R+h), and it only works if both objects are pretty much spherical or one of the objects is really small in relation to the other, as an example you and the earth, it can be assumed that you are a point mass in respect Earth. If these conditions are not there, you need to use integration.

A short answer to what you are asking would be, the gravitational force is inversely related to the square of the distance between the two objects. It is the magical 1/r^2 relation which also shows up in Coulomb's law in electrostatics. As an example if you doubled the distance between 2 objects, you would lessen the gravitational force by 4 folds. Edit: I have re-read your topic and if you need to also talk about acceleration then you need to get Newton involved with the F=ma. F would be GMm/r^2, m's will cancel on both sides and acceleration will equal to what superstring wrote on his post. Therefore the acceleration would also be cut down by 4 times.

Ps: Superstring how do u post your equations like that? I'd like to learn.
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 51 ·
2
Replies
51
Views
5K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K