Ding! Deep Drive to Center: Tracking the Ball's Flight

AI Thread Summary
The discussion focuses on calculating the maximum height of a baseball hit deep to center field and determining if it clears a 12-foot wall located 420 feet from home plate. The vertical position of the ball is given by the equation v(t) = -20t² + 103.5t + 5, while the horizontal distance is described by h(t) = 84.32t. To find the maximum height, the derivative of v(t) is set to zero, yielding t = 2.588 seconds, which is then used to calculate the height at that time. For the wall clearance, the time it takes for the ball to reach the wall is derived from h(t), and this time is substituted back into the height equation to check if it exceeds 12 feet. The calculations confirm whether the ball achieves a home run by clearing the wall.
hthorne21
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A baseball is hit deep to center field. The vertical position from home plate of the ball with respect to time is described by:
v(t) = -20t2 + 103.5t +5 in feet above home plate
The horizontal distance from home plate is described by:
h(t) = 84.32t in feet where t is in seconds
HINT: The orgin is at home plate, with the vertical axis going straight up from home plate and the horizontal axis heading out towards center field, along the flight path of the base ball
FIND:
a) the maximum height, in feet, that the ball achieves.

b) Assuming level terrain, does the ball clear the 12 foot wall located 420 feet from home plate for a home run?
 
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How would you expect to start?
 
take the derivative of v(t) the set it equal zero to get t=2.588
then what do you do with the 2.588, put it in the orginal function or do you plug it into the h(t) function
 
hthorne21 said:
take the derivative of v(t) the set it equal zero to get t=2.588
then what do you do with the 2.588, put it in the orginal function or do you plug it into the h(t) function

To determine max height, plug it in h(t).

EDIT: Sorry I misread the original. h(t) here is the horizontal distance equation.

Use V(t) equation.
 
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For b) determine when the ball arrives at the wall from your h(t) equation. Then plug that time into a height equation. V(t)
 
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