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Sheldon Cooper
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How to prove the dipole moment of an isolated quantum system in isotropic space is identically equal to zero, unless there exists an accidental degeneracy.
Thanks in advance
Thanks in advance
Cryo said:Assuming you mean electric dipole, is your statement true? Is a piece of ferroelectic in vacuum an isolated quantum system? Afterall, it could have electric dipole moment?
A dipole moment is a measure of the separation of positive and negative charges within a molecule or other quantum system. It is a vector quantity, with direction and magnitude, that describes the overall polarity of the system.
The dipole moment of an isolated quantum system is calculated by multiplying the magnitude of the charge on each particle by the distance between them, and then taking the vector sum of these individual dipole moments.
The dipole moment of a quantum system is affected by the magnitude and distribution of charges within the system, as well as the distance between these charges. It can also be influenced by external electric or magnetic fields.
The dipole moment of an isolated quantum system can provide valuable insights into the structure and properties of the system. It is also an important factor in determining the strength of intermolecular interactions, such as dipole-dipole interactions.
The dipole moment of a quantum system can be measured using techniques such as NMR (nuclear magnetic resonance) or IR (infrared) spectroscopy. These methods involve applying external electric or magnetic fields to the system and measuring the resulting changes in energy levels or vibrational frequencies.