Dipole moment of non-conducting spherical shell

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SUMMARY

The dipole moment of a non-conducting spherical shell with a surface charge distribution defined as σ = σ₀ sin 2θ is calculated using the integral p_z = ∫₀^π (σ * z * dA). The resulting dipole moment is p_z = (σ₀ a³ π²) / 2. It is confirmed that the components p_x and p_y are zero, leading to the final vector form of the dipole moment as p = (σ₀ a³ π² / 2) âₓ, where âₓ is the unit vector in the z-direction.

PREREQUISITES
  • Understanding of surface charge distributions
  • Familiarity with spherical coordinates
  • Knowledge of vector calculus
  • Ability to perform integrals involving trigonometric functions
NEXT STEPS
  • Study the derivation of dipole moments in different geometries
  • Learn about the implications of charge distributions on electric fields
  • Explore the concept of multipole expansion in electrostatics
  • Investigate the applications of dipole moments in molecular chemistry
USEFUL FOR

Students in physics or engineering, particularly those studying electromagnetism, as well as researchers interested in electrostatic properties of charged bodies.

jackxxny
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Homework Statement


I'm trying to find the dipole moment of

The surface charge distribution is:

[tex] \sigma = \sigma_{0} sin 2 \theta [/tex]

Homework Equations


The Attempt at a Solution



[tex] p_z=\int_{0}^{\pi}{\sigma* z* dA } = \int_{0}^{\pi}{(\sigma_0 \sin{2 \theta})*(acos{\theta})*(2\pi a^2 \sin{\theta}d\theta)}[/tex]

Doing so I obtain

[tex] ( \sigma_{0} a^3 \pi^2)/(2)<br /> [/tex]

Can that be the answer?
 
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You should also explicitly show (or give a good argument for why) [itex]p_x=p_y=0[/itex] and then write your final answer in vector form (since dipole moment is a vector!) as [itex]\textbf{p}=\frac{\sigma_{0} a^3 \pi^2}{2}\mathbf{\hat{z}}[/itex], but other than that it looks good to me!:approve:
 

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