Dirac Distribution with 2 Diracs

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SUMMARY

The discussion focuses on the mathematical representation of integrals involving Dirac delta functions, specifically the expression of a distribution integral with multiplicative Diracs. The integral discussed is \int f(x) \delta(t-x-l_1) \delta(t-x-l_2) dx. It is clarified that if l_1 equals l_2, the result simplifies to f(t-l), while if they are different, the integral evaluates to zero. Additionally, a multi-dimensional interpretation is provided, leading to the expression \int\int f(x,y)\delta(t_x- x- l_1)\delta(t_y- y- l_2)dxdy= f(t_x-l_1, t_y- l_2).

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divB
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Hi,

It is well known that

[itex] \int f(x) \delta(x-a) dx = f(a) \quad\mathrm{and}\\<br /> \int f(x) \delta^{(n)}(x-a) dx = (-1)^n f^{(n)}(a)[/itex]

Similarly, Is there a way to express a distribution integral with multiplicative Diracs in a compact form (e.g., a sum)?

[itex] \int f(x) \delta(t-x-l_1) \delta(t-x-l_2) dx[/itex]

Thanks,
divB
 
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The way you have written this, with a single x, is a bit misleading. What you show would be simply f(t- l) if [itex]l_1= l_2= l[/itex] and 0 if [itex]l_1\ne l_2[/itex].

But I suspect you mean a multi-dimensional version where x, t, and l are all vectors or shorthand for multiple variables. In that case,
[tex]\int\int f(x,y)\delta(t_x- x- l_1)\delta(t_y- y- l_2)dxdy= f(t_x-l_1, t_y- l_2)[/tex]
 
Thank you, your answer was exactly what I was looking for!
 

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