Direction of current in the figure?

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Homework Help Overview

The discussion revolves around determining the direction of current through a 7.00-ohm resistor in a circuit involving multiple emf sources. Participants are examining the implications of circuit polarity and the application of Kirchhoff's Laws.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the direction of current flow through the resistor, questioning the influence of battery polarity and the effects of individual emf sources. Some suggest applying superposition to analyze the current direction from each source separately.

Discussion Status

The discussion is active, with participants offering different perspectives on the current direction and suggesting methods to analyze the problem. There is no explicit consensus, as various interpretations of the circuit setup are being explored.

Contextual Notes

Participants note the manual's assertion about current direction based on battery polarity, while also expressing confusion regarding the implications of the circuit configuration. There is mention of potential ambiguity in representing the voltage source and its orientation.

ehabmozart
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Direction of current in the figure??

Homework Statement



What must the emf in the figure be in order for the current through the 7.00-ohm resistor to be 1.76A? Each emf source has negligible internal resistance. Figure

http://i239.photobucket.com/albums/ff92/anakris_24/yf_Figure_26_51.jpg

Homework Equations



Kirrchoff's Laws

The Attempt at a Solution



I know well how to use the laws but my problem here is in determining the direction of current through the 7Ω resistor. Is it up or down and why? ... In the manual it say it goes down due to polarity of the battery.. But it can actually go out of battery 1(left) and battery two?
 
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Try applying superposition. What direction does the current flow through the 7 Ω resistor due to each source when taken individually?
 
In the manual it say it goes down due to polarity of the battery.. But it can actually go out of battery 1(left) and battery two?

I don't understand your explanation. Even if the current flows out of the 24V battery into the ε battery the top end of the 7R will still be +ve wrt the bottom end.

If ε is +ve then I can't see how the current can ever flow upwards through the 7R.

Edit: It would be bad practice to show ε as -ve with the battery drawn that way around. It would be ok to show a voltage source with the arrow pointing upwards and ε marked as -ve but that's not what you have here.
 
How about solving it twice. Once assuming the current flow down through the 7R and one assuming it flow up through the 7R. What do you get?
 

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