Direction of force on circular loop.

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The discussion revolves around determining the direction of force on a circular loop carrying current. Participants emphasize using the right-hand rule and symmetry principles to analyze the forces acting on different segments of the loop. It is noted that when currents in two straight conductors are in the same direction, they attract each other, while opposite directions result in repulsion. The complexity arises in applying these principles to the entire circular loop, particularly when considering the influence of straight conductors. Ultimately, understanding the resultant forces on small segments of the loop is essential for solving the problem.
diinnoo
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Homework Statement



Find direction of force on circular loop

http://pokit.org/get/img/b886e52efb703d47d09fa6e781c74461.jpg

What would hapend if direction of the current in a straight conductor were different ?

Homework Equations



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The Attempt at a Solution



http://pokit.org/get/img/7b5d76e176716f45edb5dbf331ff9e3e.jpg

I try to do this by using right hand rule, but this is just assumptions, I am not sure is this correct or can it be done like this. When direction of current change i don't know what would happend, or how straith conductor influence? I hope you would help me ;)
 
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welcome to pf!

hi diinnoo! welcome to pf! :smile:

you're only asked for the direction, so can't you just use general principles, and symmetry?

the force between two straight currents in the same direction is … ?

in the opposite direction is … ?

now apply that to tiny bits of the circle, in pairs at opposite ends of the same diameter :wink:
 
thanks for welcome tiny-tim.

Yes only direction was asked, i think two straight current same direction force would attract each other, when they are opposit they wil reject each other, two forces.

I tried this using unit vectors i tried something like this

http://pokit.org/get/img/96569110fd7b5c1228052db376c5fecd.jpg

but i can do this onle wher direction of current is same as unit vector i or j, i don't know how to do it on whole circut. but in this examle above i again don see influence of straight current.
 
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if the loop is is placed parallel to the field there will be a couple acting on it, when it's perpendicular the two forces will be equal opposite and have the same line of action
 
I really didnt understand you, sorry, or you just can simply draw what you thought. In school we did task like this, with straight conuctor and metal frame, in same plane. Direction we find using units vector, as my example up.

http://pokit.org/get/img/23dd764ee7a54aef8c120e0932b3eb97.jpg

And this task should be on same principes but much harder :(
 
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hi diinnoo! :smile:
diinnoo said:
… two straight current same direction force would attract each other, when they are opposit they wil reject each other, two forces.

yes … so first consider two very small parts of the circle, at 12 o'clock and 6 o'clock …

which one will have the larger force, and so what will be the direction of the resultant force on the pair?

(this is similar to the question in your diagram, but your "hollow" arrows are wrong …)
diinnoo said:
http://pokit.org/get/img/23dd764ee7a54aef8c120e0932b3eb97.jpg

then consider the resultant force on four very small parts, at 1 5 7 and 11 o'clock :wink:
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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