Disc. math/logic: division & modulus proofs

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SUMMARY

This discussion focuses on proving two mathematical statements involving divisibility and congruence. The first statement asserts that if integers a, b, c, and d satisfy a | c and b | d, then ab | cd. The second statement establishes that a mod m = b mod m if a ≡ b (mod m). The discussion highlights the need for universal proofs rather than specific examples, emphasizing the importance of rigorous mathematical reasoning.

PREREQUISITES
  • Understanding of integer divisibility and notation (a | b)
  • Familiarity with modular arithmetic and congruences (a mod m)
  • Basic knowledge of mathematical proofs and logic
  • Experience with constructing universal proofs in mathematics
NEXT STEPS
  • Study the properties of divisibility in number theory
  • Learn about modular arithmetic and its applications
  • Explore techniques for constructing universal proofs in mathematics
  • Review examples of congruence relations and their implications
USEFUL FOR

Students of mathematics, particularly those studying number theory and logic, as well as educators looking to enhance their understanding of proofs involving divisibility and modular arithmetic.

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Homework Statement


Show that if a, b, c, and d are integers such that a | c and b | d, then ab | cd.

Let m be a positive integer. Show that a mod m = b mod m if a ≡ b(mod m)


Homework Equations


| means "divides," so a | b means "a divides b" or "b can be divided by a"
mod gets the remainder; a mod m means "the remainder after m is divided by a"
≡ means "is congruent to"


The Attempt at a Solution


For the proof of the first one, I can easily substitute real values:
a = 4
b = 3
c = 16
d = 9

and from that I would get

(4)(3) | (16)(9)
12 | 144

which is obviously 12, for which the statement holds true; however, since this is a universal proof and not an existential one, that statement is far from enough to prove it.


For the proof of the second statement, I am unsure about how to treat a congruency in a proof like this.

Proofs are probably my weakest point in this course, so thanks in advance for any help.
 
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If a | c, then c = ma. In the same way, d = nb.
The rest of the demonstration is up to you.
 

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