Unraveling the Stress-Strain Curve: Find Young's Modulus & Yield Strength

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Discussion Overview

The discussion revolves around determining Young's modulus and yield strength from a stress-strain curve for a material, focusing on the interpretation of units and calculations involved in a homework problem.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses confusion about the meaning of the stress axis scale set by s = 280 in units of 10^6 N/m² and how to apply it in calculations.
  • Another participant clarifies that entering a numerical answer will be interpreted as that number multiplied by 10^6 N/m², providing an example for clarity.
  • There is a repeated inquiry about the correct answer for part a, with one participant suggesting it should be 0.07 N/m², while others discuss the calculation of 280 MPa divided by 0.004.
  • Participants calculate that 280 multiplied by 10^6 leads to a value of 7e10, but they also note the interpretation by the grading program may affect the final answer.
  • One participant proposes a final answer of 70000e6 N/m² for part a and 250e6 N/m² for part b, seeking confirmation.
  • A later reply confirms part a as correct but raises a question about the definition of yield stress being used, mentioning differences in educational approaches regarding yield strength definitions.

Areas of Agreement / Disagreement

There is no consensus on the yield strength calculation, as participants mention different definitions and approaches to yield stress, indicating multiple competing views remain.

Contextual Notes

Participants express uncertainty regarding the interpretation of units and the definitions of yield strength, which may depend on the context of the problem and educational background.

Who May Find This Useful

Students studying material science or engineering, particularly those working on stress-strain analysis and related homework problems.

rgold
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Homework Statement


The figure shows the stress-strain curve for a material. The scale of the stress axis is set by s = 280, in units of 10^6 N/m2. What are (a) the Young's modulus and (b) the approximate yield strength for this material?

Homework Equations


E=stress/strain

The Attempt at a Solution


so i know that for part a i needa divide 280/.004 but I am not sure what it means to use units of 10^6. also shouldn't part b be 280? the unit that is correct is N/m^2 (its an online grading program that told me this is correct) and i cannot answer a 10^6 or any 10^... (the system won't read it) what am i not understanding?
 

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rgold said:

The Attempt at a Solution


so i know that for part a i needa divide 280/.004 but I am not sure what it means to use units of 10^6. also shouldn't part b be 280? the unit that is correct is N/m^2 (its an online grading program that told me this is correct) and i cannot answer a 10^6 or any 10^... (the system won't read it) what am i not understanding?

It means that if you enter [answer] this will be interpreted as [answer] x 106 N/m2
e.g. if you put in 6 your answer will be interpreted as 6 Mega Pascals
 
so shouldn't the answer to part a be .07 n/m^2?
 
rgold said:
so shouldn't the answer to part a be .07 n/m^2?

What are the units of the '280' ?

What does 280 / 0.004 equal? What are it's units?
 
280*10^6
so then the answer would be 7e10 but rly 7e4 bc of how the the program will interpret it?
 
rgold said:
280*10^6
so then the answer would be 7e10 but rly 7e4 bc of how the the program will interpret it?

You still didn't provide any units but yes you are on the right track.

280 MPa / 0.004 = 70 GPa = 70 000 MPa = 70 000 x 106 N / m2
 
so my final answer would be 70000e6 N/m^2 for part a and 250e6 N/m^2 for part b?
 

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