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Discontinuous Conduction Mode (Buck-Converter)

  1. Jun 14, 2009 #1
    Why does DCM work the way it does?

    Because it makes no sense (To me, obviously).

    Not how it works. Why it works. The intuitive form, to me, would be that a lighter load would mean more time before the loop discharges, (due to tau = L/R) but apparently it's the other way around in a buck converter.
     
  2. jcsd
  3. Jun 17, 2009 #2

    berkeman

    User Avatar

    Staff: Mentor

    DCM happens because the average output current is below half of the delta-I through the inductor. This TI application note describes it pretty well:

    http://focus.ti.com/general/docs/lit/getliterature.tsp?baseLiteratureNumber=SLVA057

    .
     
  4. Jun 18, 2009 #3
    Thank you, I'll see if I can make sense of this.
     
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