Discover the Depth of an Opaque Cylindrical Tank with this Optics Question

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SUMMARY

The discussion focuses on calculating the depth of an opaque cylindrical tank filled with water, which has a diameter of 3 meters. When sunlight reaches an angle of 28 degrees above the horizon, it fails to illuminate part of the tank's bottom. Participants suggest using trigonometric principles, specifically the sine or cosine rule, to determine the tank's height, concluding that the depth is approximately 1.41 meters. The reasoning behind the lack of illumination at the bottom is attributed to the low angle of sunlight during the afternoon.

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An opaque cylindrical tank with an open top has a diameter of 3m and is completely filled with water. When the afternoon sun reaches an angle of 28o above the horizon, sunlight cease to illuminate and part of the bottom of the tank. How deep is the tank?

I don't understand how to approach this question but more importantly I guess I should ask why doesn't the bottom part of the tank is not illuminated?
 
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Hi,
To make things easier i suggest you to draw a schematic..
I think it is simple.Draw a cylinder..that is enough..Now draw a line..with 28 degree to the surface of the tank or to the bottom of the tank..now you can apply sin or cosine rule to get the height of cylinder? By this way i got 1.41 m height of cylinder.
good luck
 
semc said:
… why doesn't the bottom part of the tank is not illuminated?

Hi semc! :smile:

It's afternoon, so the sun is going down …

even if the tank was empty, when the sun is low enough, the sunlight won't light up all the bottom of the tank. :wink:
 

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