Discover the Solution for tan(x)=sin(2x) in Just a Few Simple Steps!

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SUMMARY

The discussion focuses on solving the equation tan(x) = sin(2x) by expressing both sides in terms of sine and cosine functions. Participants suggest using the identities tan(x) = sin(x)/cos(x) and sin(2x) = 2sin(x)cos(x) to derive a solution. The method involves squaring both sides and applying the difference of squares formula, (a-b)² = (a+b)(a-b), to find intersection points. This approach is recommended for obtaining accurate closed-form solutions without discarding potential solutions.

PREREQUISITES
  • Understanding of trigonometric identities, specifically tan(x) and sin(2x).
  • Familiarity with algebraic manipulation, including squaring equations and using the difference of squares.
  • Basic knowledge of graphing functions to identify intersection points.
  • Proficiency in solving trigonometric equations.
NEXT STEPS
  • Study the derivation of trigonometric identities, particularly tan(x) and sin(2x).
  • Learn about solving equations involving trigonometric functions using graphical methods.
  • Explore the implications of squaring both sides of an equation in trigonometric contexts.
  • Research methods for finding closed-form solutions in trigonometric equations.
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Mathematics students, educators, and anyone interested in solving trigonometric equations or enhancing their understanding of trigonometric identities and algebraic techniques.

princiebebe57
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How do you find the solution tan(x)=sin(2x)? :confused:
 
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Can you express both sides in terms of sin(x) and cos(x)? That might be a good place to start.
 
No...do i have to do that to find all the solution points?
 
princiebebe57 said:
No...do i have to do that to find all the solution points?

You could plot them and look for the intersection points.
But cristo's suggestion would probably yield more accurate ["closed form"] answers. (Be careful not to inadvertently throw away solutions.)
 
Last edited:
You can easily do it using the fact that:

<br /> \begin{array}{l}<br /> \tan x \equiv \frac{{\sin x}}{{\cos x}} \\ <br /> \sin (2x) \equiv 2\sin x\cos x \\ <br /> \end{array}<br />
 
square both sides...then make use of (a-b)^2 = (a+b)(a-b)
 
unscientific said:
square both sides...then make use of (a-b)^2 = (a+b)(a-b)

um...
(a-b)^2 = a^2 - 2ab + b^2
a^2 - b^2 = (a+b)(a-b)
 

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