If I have the following relation:
tan(2x) = (B/2) / (A - C)
but tan(2x) = sin(2x) / cos(2x)
How do I obtain an expression for sin(x) and cos(x) in terms of the constants, B,A,C only?
cos(2x) = 1- 2 sin^2(x)
The Attempt at a Solution
I can't just consider B/2 as the opposite and A-C as the adjacent to find the hypotenuse:
sin(x) = O/H = (B/2)/[B^2/4 +(A-C)^2]^1/2