Discover the Solution to Sin(arctan(x/4)) with Expert Guidance

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SUMMARY

The discussion focuses on solving the expression Sin(arctan(x/4)). The user effectively sets up a right triangle where the opposite side is x and the adjacent side is 4, leading to the conclusion that θ = arctan(x/4). Through the application of the Pythagorean theorem, the user derives the sine of angle A as Sin(A) = x√(x² + 16) / (x² + 16), confirming the correctness of the solution.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and tangent.
  • Familiarity with the Pythagorean theorem and its application in right triangles.
  • Knowledge of inverse trigonometric functions, particularly arctan.
  • Basic algebra skills for manipulating expressions and rationalizing denominators.
NEXT STEPS
  • Explore the properties of inverse trigonometric functions and their applications.
  • Learn about the derivation of trigonometric identities using right triangles.
  • Study the Pythagorean theorem in more complex geometric contexts.
  • Investigate the relationship between trigonometric functions and calculus, particularly in limits and derivatives.
USEFUL FOR

Students studying trigonometry, educators teaching mathematical concepts, and anyone looking to enhance their understanding of inverse trigonometric functions and their applications in geometry.

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[Mentor's note: This thread was originally posted in a non-homework forum, so it doesn't follow the homework template.]

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Sin(arctan(x/4))= ?

Been over 2 years since I've done some math, a little help please?
 
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Set up a right triangle with sides x and 4, so that the tangent of one of the angles is x/4, i.e., tanθ=x/4. Then θ=tan^{-1}(x/4) . From the drawing, figure out the value of sinθ.
 
It might help you if you draw a triangle and split the expression above into component parts.

First, how would you triangle look if you were to show what arctan(x/4) meant?
 
Ok I:

Drew a triangle in quadrant 1 to represent x/4 and labeled the angle A for random sake
then used Pythagorean theorem to find the hyp
after solving for sign and rationalizing I came up with:

SinA= (x(√(x^2)+16)/((x^2)+16) ------ √ ending after the first 16
sound right?
 
Yes, ##\sin(A)=x\frac{\sqrt{x^2+16}}{x^2+16}##.

ehild
 

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