Discrete Fourier Transform (DFT) Matching

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Signal 1 corresponds to DFT 3 as it represents a constant function, while Signal 6 matches DFT 5, being an impulse. Signal 2, a sampled cosine, aligns with DFT 8, and Signal 4, with two cosine cycles, corresponds to DFT 2. Signals 7 and 8 are identified as undersampled cosines, with Signal 7 featuring a varying amplitude envelope and Signal 8 representing a pure cosine, leading to DFT 6. The DFT scale is similar to an FFT spectrum, ordered from zero frequency to positive frequencies, followed by negative frequencies.
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Homework Statement


Match each discrete-time signal with its DFT:

dfts.png


Homework Equations

The Attempt at a Solution



I am mainly confused about Signal 7 and Signal 8.

Signal 1 is the discrete equivalent to a constant function, therefore its DFT is an impulse (Dirac ##\delta##), so it corresponds to DFT 3.

DFT of an impulse is a constant. Therefore Signal 6 corresponds to DFT 5.

Signal 2 is a sampled version of a full period of a cosine. So we expect ##X(1)## and ##X(-1)## to be nonzero (##X(-1)## really is ##X(N-1)=X(25)##). Therefore Signal 2 corresponds to DFT8.

By similar arguments, Signal 4 has exactly 2 cycles of a cosine and corresponds to DFT2. And Signal 3 has one and a half periods of a cosine, as we do not have complete periods we should expect spectral leakage, so signal 3 corresponds to DFT4 (the main peaks are around 1 & 2 plus negative frequencies). Likewise, Signal 5 corresponds to DFT7.

Here is a summary of the results so far:

table.jpg


Only Signals 7 & 8 and DFT 6 & 1 are left:

dftset.png
What do signals 7 and 8 represent? Is Signal 7 an undersampled cosine? How do we go about matching them with their corresponding DFTs?

Any explanation would be greatly appreciated.
 
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Could you please clarify what the scale of the DFT represents? Is it the the same order as the output of an FFT (from 0 to highest positive frequency, followed by lowest negative frequency back to 0)?

roam said:
What do signals 7 and 8 represent? Is Signal 7 an undersampled cosine? How do we go about matching them with their corresponding DFTs?
Both can be see as undersampled cosines, with Signal 7 being a cosine with a varying amplitude envelope.
 
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DrClaude said:
Could you please clarify what the scale of the DFT represents? Is it the the same order as the output of an FFT (from 0 to highest positive frequency, followed by lowest negative frequency back to 0)?

It is similar to the spectrum of an FFT which is not fftshifted. The zero-frequency component (DC) is the first element (##r=0##). Then it is the positive frequencies, but I think it is lowest to largest, followed by negative frequencies.

Both can be see as undersampled cosines, with Signal 7 being a cosine with a varying amplitude envelope.

Yes, this is right. Any ideas how to identify the DFT for each signal?
 
roam said:
Any ideas how to identify the DFT for each signal?
What case would correspond to a single frequency?
 
DrClaude said:
What case would correspond to a single frequency?

Is it Signal 8?

So, the spectrum of Signal 8 is DFT6? What would be a good explanation? Signal 7 looks like at least two cosine waves being heterodyned (i.e. a cosine wave contained in a lower frequency cosine envelope).
 
roam said:
So, the spectrum of Signal 8 is DFT6? What would be a good explanation? Signal 7 looks like at least two cosine waves being heterodyned (i.e. a cosine wave contained in a lower frequency cosine envelope).
That's basically it. Signal 8 corresponds to a pure cosine sampled twice per oscillation period, and therefore has a single frequency. The effect of changing the envelop (modulating the amplitude) is a spreading out of the frequency, as given by DFT1 (you can see it as an "uncertainty" in the frequency due to the limited time, or pulse nature, of the signal, or due to the fact that the signal is similar to a beat coming from overlapping signals of similar frequencies).
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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