"Six men and 6 females are to be seated around a circular table. Every person must be sitting opposite of another person of the same sex. How many different seatings are possible?"(adsbygoogle = window.adsbygoogle || []).push({});

* Ok here's my logic, If you have 12 people, and just want to seat them, you can do so in 11! ways...

* So if you sit 3 men anywhere, then opposite you can sit the rest of the men... I think this would be like P(12 3)...

* Then you just seat the women in the rest of the seats; 5! ways...

So total ways, would be something along the lines of P(12 3) + 5!. I don't think that's right, so that's why I'm here asking for help.

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# Homework Help: [Discrete Math] Circular Permutations

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