Disp. with Constant Accel. Formula Help

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SUMMARY

A jet plane landing at a velocity of +100 m/s with a maximum deceleration of -5.0 m/s² can successfully land on an 800-meter runway. The critical calculations involve determining the time to stop and the stopping distance using the equations of motion. The correct approach requires using the second equation, Δx = (1/2)(v_i + v_f)Δt, after accurately calculating the time to stop. The initial attempt at calculating time was flawed due to sign errors, which must be corrected for accurate results.

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Homework Statement


A jet plane lands with a velocity of +100 m/s and can accelerate at a maximum rate of -5.0 m/s2 as it comes to rest. Can this plane land at an airport where the runway is 800 meters long?

v_i = +100 m/s
a = -5.0 m/s^2

Homework Equations


The only equations in the chapter are as follows, but I don't think either can help me:
a_{avg} = \frac{\Delta x}{\Delta t}
\Delta x = \frac{1}{2}(v_i +v_f)\Delta t

The Attempt at a Solution


I have attempted the following, but the answer does not seem to make any sense to me, since I need a distance and not a time.

\frac{+100 m/s}{-5.0 m/s^2} = -20 s
 
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shyboyswin said:

Homework Statement


A jet plane lands with a velocity of +100 m/s and can accelerate at a maximum rate of -5.0 m/s2 as it comes to rest. Can this plane land at an airport where the runway is 800 meters long?

v_i = +100 m/s
a = -5.0 m/s^2

Homework Equations


The only equations in the chapter are as follows, but I don't think either can help me:
a_{avg} = \frac{\Delta x}{\Delta t}
\Delta x = \frac{1}{2}(v_i +v_f)\Delta t

The Attempt at a Solution


I have attempted the following, but the answer does not seem to make any sense to me, since I need a distance and not a time.

\frac{+100 m/s}{-5.0 m/s^2} = -20 s
Shyboyswin, welcome to PF! Your first equation is not correct, looks like you may have made a typo error, because you have used the correct magnitude values in your calculation for time, although you're messing up your plus and minus signs. Once you get the time, use your 2nd equation to calculate the required stopping distance.
 

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