Displacement of a car before it stops

[missashley]

Homework Statement

A 2410 kg car traveling to the west at 22.6 m/s slows down uniformly.

It takes 6.13355 seconds for the the car to come to a stop if the force on the car is 8880N to the east.

What is the car's displacement during the time it takes to stop? Answer in m

Homework Equations

d = vit + .5at^2

The Attempt at a Solution

Fnet=m*a=F
=(2410)a=8880
a=3.68m/s2
d=vit-.5at^2
=22.6*6.13355+(.5)(3.68)(6.13355)^2
=207.8387m

its not 207.8387 or 69.396

 

[rl.bhat]

=22.6*6.13355+(.5)(3.68)(6.13355)^2
Motion is retarding . So acceleration should be negative.
=22.6*6.13355-(.5)(3.68)(6.13355)^2