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Displacement of a vector (Really simple)

  1. Jan 26, 2008 #1
    [SOLVED] Displacement of a vector (Really simple)

    1. The problem statement, all variables and given/known data
    A ship sets out to sail to a point 106 km due north. An unexpected storm blows the ship to a point 128 km due east of its starting point. (a) How far (in km) and (b) in what direction (as an angle from due east, where north of east is a positive angle) must it now sail to reach its original destination?


    2. Relevant equations



    3. The attempt at a solution
    I have (a) = 166.1926593 which is correct and to find (b) I'm just using tan^(-1)(106/128) = 39.6290053 but this isn't correct? Am I supposed to be taking the complement of this angle?
     
  2. jcsd
  3. Jan 26, 2008 #2
    What you've solved for is the angle inside the right angled triangle, from what I gather. If you take for example, the up/down and left/right axes to be the directions and draw them in on the triangle with the new starting point (128 east of the original starting point) as the origin, that should help. The problem tells you to take the angle from the east, with north of east as positive, so find the angle from the east axis to the hyp. of the triangle. That is the supplementary angle to the one you have found and it should be the answer you are looking for. :)
     
  4. Jan 26, 2008 #3
    Well the opposing angle would be 50.3709947 which is also incorrect. I would have thought the angle would have just been 90 seeing as its only involving direct N and direct E.
     
  5. Jan 26, 2008 #4
    You should be looking for the supplementary angle, which is 180 degrees-theta. What you've found is the complementary angle.
     
  6. Jan 26, 2008 #5
    Ah I gotcha thanks
     
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