1. The problem statement, all variables and given/known data A 0.170 kg hockey puck is initially moving at 21.2 m/s [W] along the ice. The coefficient of kinetic friction for the puck and the ice is 0.005. (a) What is the speed of the puck after traveling 58.5 m? (b) After being played on for a while, the ice becomes rougher and the coefficient of kinetic friction increases to 0.047. How far will the puck travel if its initial and final speeds are the same as before? 2. Relevant equations v2^2=v1^2+2ad Fnet=ma Ff=μkFn 3. The attempt at a solution a) FN=9.8(0.170)=1.666 Ff=0.005(1.6660)=0.00833 Fnet=ma 0.00833=0.170a =0.049 v2^2=v1^2+2ad v2^2=(21.2)^2+2(0.049)(58.5) v2=21.3, but the answer is 21.1 b)Ff=0.047(1.666) Ff=0.078302 0.078302=0.170a=0.4606 v2^2=v1^2+2ad I'll use the correct v2 21.1^2=21.2^2+2(0.4606)d -4.23=0.9212d d=-4.59 but the answer is 6.24 Not sure where I'm going wrong?