Displacement of zigzaging dust particle

In summary, the particle of dust travels a distance of v in time t. The length of the displacement vector after N steps is d\sqrt{N}.
  • #1
Pseudopro
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0

Homework Statement


A particle of dust is bombarded by air molecules and follows a zigzag path at constant speed v.
(a)Assuming each step has a length d, find the distance traveled by the dust particle in time t.
(b)What is the length of the displacement vector after N steps where N is large? Assume that each step is taken in a random direction on the plane. (This problem assumes you are familiar with the scalar product of two vectors.

Homework Equations


v2=(v12+v22+...+vN2)/N

The Attempt at a Solution


The answer to part (a) seemed quite obvious: vt.
However, part (b) isn't so easy. I've been able to get the answer d[tex]\sqrt{N}[/tex] by doing vt=t x sqrt[(v12+v22+...+vN2)/N] but this is getting the answer for the sake of it. My method doesn't actually make any sense because it can cancel out to nothing. Please help!
(I believe this is called Brownian motion?) (the thing I don't get is how do I use dot product in this instance?)
 
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  • #2
Hi Pseudopro! :smile:

Hint: if you add two vectors whose lengths are fixed as a and b, but whose directions are random,

what is the average magnitude of the sum of those vectors? :wink:
 
  • #3
(a+b)/2?
 
  • #4
uhh? :confused:

call the angle θ, and work out the magnitude! :rolleyes:

(and then average over θ)
 
  • #5
Sorry, I don't think I'm doing this properly (or I don't have the knowledge).

Are you looking for something like this? [tex]\sqrt{a^{2}+b^{2}-2abcos\theta}[/tex]
 
  • #6
That's it! :smile:

ok, since θ can be anything, the average value of that is (roughly) … ? :wink:

(and then try the same thing for n vectors)
 
  • #7
average value of cos would be 0.5 I think - so it would end up as d... (wait does the assumption from part (a) still hold?) I don't see how I can get sqrt N... if I put d back into the equation, I just get exactly the same thing back again...
 
  • #8
Pseudopro said:
average value of cos would be 0.5 I think …

uhh? :confused: average value of cos is zero
 
  • #9
oh yeah. my bad...
 
  • #10
Thanks a lot for your guidance. :smile: I've got it now :approve:
 
  • #11
I am also doing this problem and understand the hints above, but I don't understand how the answer is d[itex]\sqrt{N}[/itex]. Can someone help?? :uhh:
 
  • #12
I am also doing this problem and understand the hints above, but I don't understand how the answer is d√N. Can someone help?? :uhh:
 

1. What causes zigzagging in dust particles?

The zigzagging motion of dust particles is caused by the random collisions with air molecules. These collisions create a chaotic movement in the particle's path, resulting in a zigzag pattern.

2. Can zigzagging dust particles affect air quality?

Yes, zigzagging dust particles can affect air quality by increasing the concentration of dust particles in the air. This can lead to respiratory problems and reduced visibility.

3. How does the size of a dust particle affect its displacement?

The size of a dust particle can affect its displacement by influencing its air resistance and weight. Smaller particles are more easily affected by air molecules, making them more likely to zigzag and travel longer distances.

4. Is the displacement of zigzagging dust particles predictable?

No, the displacement of zigzagging dust particles is not predictable due to the random nature of their motion. Factors such as air temperature and pressure can also affect the displacement of these particles.

5. How does the displacement of zigzagging dust particles impact weather patterns?

The displacement of zigzagging dust particles can impact weather patterns by affecting the concentration of particles in the atmosphere. This can lead to changes in cloud formation and precipitation, as well as influence wind patterns.

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