Displacement Operator: Explaining Dirac's Equality

  • Context: Graduate 
  • Thread starter Thread starter bikashkanungo
  • Start date Start date
  • Tags Tags
    Operator
Click For Summary

Discussion Overview

The discussion revolves around the displacement operator as presented in Dirac's text, specifically focusing on the equality involving the limit of the expression [D*exp(iy)-1]/δx and its relationship to [D-1+iy]/δx. Participants explore the implications of the Taylor expansion of the exponential function and the assumptions made regarding the limits as δx approaches zero.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant questions how the equality [D*exp(iy)-1] = [D-1+iy] holds, suggesting that the Taylor expansion becomes exact if y tends to zero.
  • Another participant expresses concern that there should be a D in front of the iy and iax, implying a possible misprint in Dirac's text.
  • A different participant mentions that they encountered the same expression in a lecture by Dr. Fitzpatrick, suggesting a potential reliance on Dirac's work.
  • One participant critiques Dirac's treatment of the infinitesimal displacement operator as unrigorous and expresses disappointment.
  • Another participant offers their interpretation of the equality, emphasizing the irrelevance of the phase factor exp(iy) and questioning the assumption that y tends to zero as δx approaches zero.
  • There is a request for clarification on the Taylor expansion for the exponential and the reasoning behind the assumption regarding y.

Areas of Agreement / Disagreement

Participants express differing views on the correctness of Dirac's formulation and the assumptions made in the derivation. There is no consensus on whether the treatment is rigorous or if the expressions are correctly represented.

Contextual Notes

Participants note potential limitations in Dirac's treatment, including assumptions about the behavior of y and the validity of the Taylor expansion. The discussion highlights the need for careful consideration of the definitions and conditions under which the limits are taken.

bikashkanungo
Messages
9
Reaction score
0
In Dirac's text regarding displacement operator it is given that :-
lim(δx→0)⁡[D*exp⁡(iy)-1]/δx =lim(δx→0) [D-1+iy]/δx = dx + iax
Where dx = displacement operator =lim(δx→0) [D-1]/δx
ax = lim(δx→0) y/ δx
and it is assumed that y tends to zero as δx tends to zero
can anyone explain how the equality of ⁡[D*exp⁡(iy)-1] = [D-1+iy] holds good ??
 
Physics news on Phys.org
bikashkanungo said:
In Dirac's text regarding displacement operator it is given that :-
lim(δx→0)⁡[D*exp⁡(iy)-1]/δx =lim(δx→0) [D-1+iy]/δx = dx + iax
Where dx = displacement operator =lim(δx→0) [D-1]/δx
ax = lim(δx→0) y/ δx
and it is assumed that y tends to zero as δx tends to zero
can anyone explain how the equality of ⁡[D*exp⁡(iy)-1] = [D-1+iy] holds good ??

If y tends to zero then the taylor expansion of the exponential becomes exact. I think that's what he's getting at. Although if this were the case the limit would be D iy +D-1. Did you leave out parentheses?
 
@nileb : No its exactly as given in Dirac's book , I did not leave out any paranthesis
 
I'm fairly sure there should be a D in front of the iy and iax. Perhaps a misprint? Does he use the formula ever again?
 
I think Fitzpatrick copy-pasted from Dirac...Anyway, Dirac's unrigorous treatment looks quite dubious.
 
Hi! I was reading the Dirac's text and I was very disappointed for his treatments of the infinitesimal displacement operator, so I found this post and I want to add a reply. I don't know if what I want to say is right but is my interpretation of the equality that appears in dirac's book:

lim(δx→0)⁡[D*exp⁡(iy)-I]/δx =

Obs. I is the Identity operator

lim(δx→0) exp(iy)*[D-exp(-iy)*I]/δx =

Obs. now, in such expression I can say that the exp(iy) in front of all is an arbitrary phase factor and so is completely irrelevant (the important thing is the relative phase factor between the two operators D and I that appear in the equation)

lim(δx→0) [D-exp(-iy)*I]/δx =

lim(δx→0) [D-I+iy*I]/δx =

dx + ax

The thing that I don't understand yet is the taylor expansion for the exponential, I don't understand why he assume y → 0 as δx→0

Please anyone can write me back to tell me if I'm completely wrong?? Thanks;)
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 14 ·
Replies
14
Views
3K