Explicit form of annihilation and creation operators for Dirac field

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• QFT1995
In summary: For free fields, for which a mode decomposition, usually in terms of the momentum-spin single-particle eigenbasis, makes sense. The fermionic case is not much different from the bosonic one. The only difference is that you have anti-commutators instead of commutators, i.e.,$$\{ \hat{a}(\vec{p},\sigma),\hat{a}(\vec{p}',\sigma') \} =0, \quad \{ \hat{a}(\vec{p},\sigma),\hat{a}^{\dagger}(\vec{p}',\sigma') \} = N QFT1995 I'm unclear on what exactly an annihilation or creation operator looks like in QFT. In QM these operators for the simple harmonic oscillator had an explicit form in terms of$$
\hat{a}^\dagger = \frac{1}{\sqrt{2}}\left(- \frac{\mathrm{d}}{\mathrm{d}q} + q \right),\;\;\;\hat{a} = \frac{1}{\sqrt{2}}\left(\frac{\mathrm{d}}{\mathrm{d}q} + q \right)
$$however I cannot find any explicit terms for these in QFT. My question is, is it possible to formulate an expression for them in terms of a differential operator or do we just assume that they exist in QFT? I am particularly interested in the Massive Thirring Model (Dirac field in 1+1D with self interactions). They act on quite an structured set of functions. It is possible to write them explicitly but consider that a creation operator ##a_{p}^{\dagger}## acting on a one particle state ##f\left(q\right)## maps it into a two particle state ##f\left(p,q\right)## also they need to be smeared or else the result won't be a state. The creation operator for example acts as:$$a_{p}^{\dagger} f = \delta\left(q-p\right)\otimes f, \quad f \in \mathcal{H}_{-\frac{1}{2}}\left(\mathbb{R}^{3}\right)^{\otimes n}$$This isn't really usable in a analytic sense like the ones from QM since they don't map between functions of the same fixed number of variables. One just needs their algebraic properties. vanhees71 and weirdoguy QFT1995 said: My question is, is it possible to formulate an expression for them in terms of a differential operator It is possible, in terms of functional derivatives. See e.g. https://www.amazon.com/dp/0201360799/?tag=pfamazon01-20 Eq. (10.40). vanhees71 Thank you both. Demystifier said: It is possible, in terms of functional derivatives. See e.g. https://www.amazon.com/dp/0201360799/?tag=pfamazon01-20 Eq. (10.40). I checked the reference you provided and it helped so thank you. Do you know what the creation and annihilation operators would look like for a fermionic field? I don't have much experience with the path integral formalism and I'm struggling with the manipulations. Well, the path integral is well worth learning when dealing with QFT. It makes some issues much more simple (though it's still complicated enough). Particularly quantizing local gauge symmetric theories (among them the Standard Model of HEPs) is much more complicated in the (covariant) operator formalism. As it turns out the path integral for fermions needs the introduction of "Grassmann numbers" rather than usual complex numbers to describe the fields integrated over in the path integral. A good textbook introducing QFT in the "path-integral-first" way is D. Bailin, A. Love, Introduction to Gauge Field Theory, Adam Hilger, Bristol and Boston (1986). dextercioby QFT1995 said: I checked the reference you provided and it helped so thank you. Do you know what the creation and annihilation operators would look like for a fermionic field? I don't have much experience with the path integral formalism and I'm struggling with the manipulations. For fermions you need functional derivatives with respect to Grassmann valued fields. See e.g. my http://de.arxiv.org/abs/quant-ph/0302152 Eqs. (9) and (11). vanhees71 Of course you can also work in the operator formalism. For gauge theories it's a pretty complicated eneavor though; I'd recommend to learn only QED in the operator formalism, then learn path-integral methods and then go to the non-Abelian case. For free fields, for which a mode decomposition, usually in terms of the momentum-spin single-particle eigenbasis, makes sense. The fermionic case is not much different from the bosonic one. The only difference is that you have anti-commutators instead of commutators, i.e.,$$\{ \hat{a}(\vec{p},\sigma),\hat{a}(\vec{p}',\sigma') \} =0, \quad \{ \hat{a}(\vec{p},\sigma),\hat{a}^{\dagger}(\vec{p}',\sigma') \} = N(\vec{p}) \delta^{(3)}(\vec{p}-\vec{p}') \delta_{\sigma \sigma'}.
The normalization factor is a matter of convention. Some textbooks use the simple but non-covariant one, ##N(\vec{p})=1##, others use the covariant one with ##N(\vec{p})=(2 \pi)^3 2 E_{\vec{p}}##.

1. What are annihilation and creation operators for Dirac field?

Annihilation and creation operators are mathematical operators used in quantum field theory to describe the creation and annihilation of particles. In the case of Dirac field, these operators are used to describe the creation and annihilation of fermions, such as electrons and quarks.

2. What is the explicit form of annihilation and creation operators for Dirac field?

The explicit form of annihilation and creation operators for Dirac field is given by the Dirac equation, which is a relativistic wave equation that describes the behavior of fermions. The operators are represented by matrices, with the annihilation operator corresponding to the negative energy solution of the Dirac equation and the creation operator corresponding to the positive energy solution.

3. How are annihilation and creation operators related to each other?

Annihilation and creation operators are related to each other through their commutation and anticommutation relations. These relations describe how the operators act on the quantum states of a system and are crucial for understanding the behavior of particles in quantum field theory.

4. What is the significance of annihilation and creation operators in quantum field theory?

The use of annihilation and creation operators in quantum field theory allows for a more efficient and elegant description of particle interactions. They also play a crucial role in the formulation of quantum field theories, such as the Standard Model, which is the current framework for understanding the fundamental particles and forces in the universe.

5. How are annihilation and creation operators used in practical applications?

Annihilation and creation operators are used in practical applications, such as in the calculation of scattering amplitudes and cross sections in particle physics experiments. They are also used in the formulation of quantum field theories for studying phenomena in condensed matter physics, such as superconductivity and superfluidity.

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