Displacement & Pythagorean Theorem: Triangle ABC

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Discussion Overview

The discussion revolves around the relationship between displacement and the Pythagorean theorem in the context of vector addition, particularly in triangle ABC. Participants explore the definitions and implications of vectors, distance, and displacement, as well as the conditions under which the Pythagorean theorem applies.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that adding vectors a and b results in vector c, questioning the application of the Pythagorean theorem, which they associate with distance rather than displacement.
  • Another participant clarifies that the Pythagorean theorem applies specifically when vectors a and b are orthogonal, and suggests using the law of cosines for general vectors.
  • A third participant references their book's treatment of vector addition using coordinates, expressing confusion about whether they are measuring distance or displacement.
  • One participant explains that displacement is a type of vector quantity, contrasting it with total distance traveled, which involves the magnitudes of the vectors.
  • Another participant provides a link to additional resources on vector addition, suggesting further exploration of the topic.
  • A participant raises a question about the relationship between displacement vectors and Euclidean vectors, seeking clarification on the definitions.
  • Another participant questions the term "Euclidean vectors," prompting a discussion about the definitions used in different contexts.
  • A later reply acknowledges the ambiguity in the definition of "Euclidean vector," noting that it may vary between physicists and mathematicians.

Areas of Agreement / Disagreement

Participants express varying interpretations of the relationship between displacement and distance, as well as the definitions of vectors. There is no consensus on the definitions or the implications of the Pythagorean theorem in this context, indicating multiple competing views.

Contextual Notes

Participants highlight the dependence on definitions and the conditions under which the Pythagorean theorem applies, particularly regarding the orthogonality of vectors. There is also mention of ambiguity in terminology between different fields.

lrl4565
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Alright, we have triangle abc with hypotenuse c. So, if you add vector a and vector b, the answer is vector c.

Now, according to the pythagorean theorem, this would not make sense. But the pythagorean theorem is DISTANCE. I am guessing that this phenomenon has something to do with using displacement?
 
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Note, that the pythagorean theorem corresponds to the particular geometric situation where vector a and b are orthogonal on each other and in this case, the pythogorean theorem relates the length of the three vectors. For general vectors a and b, you need the law of cosine that includes the angle between a and b in order to related the length of a and b with the length of c.
 
My book says vector a + vector b = vector c. It uses (x,y) coordinates.

Vector a: (x1,y1)
Vector b: (x2,y2)
Vector c: (x1+x2, y1+y2)

Filip Larsen, what you just described gives me the magnitude of the displacement.

Am I measuring distance or displacement? Is the vector all about displacement?
 
Displacement is only one example of a vector quantity. It's the first one that most physics textbooks introduce. There are many others: velocity, acceleration, force, momentum, angular momentum, electric field, magnetic field, ...

In your example, the total distance traveled would be the sum of the lengths (magnitudes) of the displacement vectors a and b:

d_{total} = \sqrt{x_1^2 + y_1^2} + \sqrt{x_2^2 + y_2^2}

The total displacement would be simply the vector c, which has magnitude

\sqrt{(x_1 + x_2)^2 + (y_1 + y_2)^2}

and a direction (angle) given by

\tan \theta = \frac{y_1 + y_2}{x_1 + x_2}
 
What do you mean by "Euclidean vectors"?
 
Naty1's link is for Euclidean Vectors
 
Oh, silly me :wink: should've clicked on that.

From what I read in the article, it seems like a displacement vector is just one example of a Euclidean vector. Although it kind of depends on how you define "Euclidean vector" - there's a bit of ambiguity in the article, probably because different groups of people (e.g. physicists vs. mathematicians) have different definitions for the term.
 

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