How many ways can one reach point (a,b) starting from (0,0)?

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SUMMARY

The discussion centers on calculating the number of ways to reach the point (a,b) from (0,0) in a coordinate system using unit displacements. The solution involves a total of a+b displacements, with a displacements in the direction of d1 and b displacements in the direction of d2. The number of unique paths is determined by the binomial coefficient, represented as &binom{a+b}{a}. This method accurately describes the combinatorial nature of the problem.

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Homework Statement



We fit the plane with a coordinate system, and we consider the set of points with coordinates in ##\mathbb{N}\times\mathbb{N} ##. To link two points in this coordinate system, we only allow unit displacements, and only increasing displacements.
In how many ways can one reach point ##(a,b)## starting from ##(0,0)## ?

Homework Equations



##d_i## is the direction of axis ##i##, ##i = 1,2##

The Attempt at a Solution



There will be ##a## displacements in direction ##d_1##, and ##b## displacements in direction ##d_2##, for a total of ##a+b## displacements.
Since there are only two kinds of displacements, it fully describes a possible way to choose once and for all a direction, and to assign an order of appearance in ##[[1..a+b]]## for each displacements in this direction, among all displacements.
Let us choose ##d_1##. The number of possible ways to link ##(0,0)## and ##(a,b)## is reduced to finding the number of parts of cardinal ##a## in ##[[1..a+b]]##, which is ##\binom {a+b} {a}##.
Do you agree with the reasoning ?
 
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Hi geoffrey:

Looks good to me.

Regards,
Buzz
 
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Ok, thanks !
 

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