Dissipation of Power by Resistors

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Homework Help Overview

The discussion revolves around the dissipation of power by resistors in a circuit, focusing on the application of relevant equations to determine the power dissipated across individual resistors based on given values.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between voltage, current, and resistance, with some questioning the initial approach to calculating power. There is discussion about the need to determine the current through the resistors and the correct application of power formulas.

Discussion Status

Some participants have provided guidance on how to approach the problem, suggesting that the original poster should calculate the current first and then use it to find the power dissipated by each resistor. Multiple interpretations of the problem are being explored, particularly regarding the use of total voltage versus individual resistor values.

Contextual Notes

There appears to be some confusion regarding the application of voltage across the resistors and the overall circuit setup, which may affect the calculations. The original poster expresses uncertainty about the next steps in their solution process.

cwesto
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Homework Statement



untitled.jpg


Homework Equations



P=IV
I=V/R
P=(V/R)V
R=V2/R

The Attempt at a Solution



PR1: 122/12=12
PR2: 144/18

I'm not sure what to do from here. Thanks for any input and help!
 
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Maybe start with how much current is passing through the resistors?

Your attempt incorrectly tried to use the total Voltage of the supply across the resistors singly. The question wants to know the power dissipated by each resistor.

Once you have the current then won't the power for any resistor be P = I2R ?
 
I=V/R
Rtotal=12+18
I=12/30
PR1=RI2
PR1=12*[tex]\frac{2}{5}[/tex]*[tex]\frac{2}{5}[/tex]
PR1=48/25

PR2=[tex]\frac{72}{25}[/tex]=2.88
Thanks!
 
cwesto said:
I=V/R
Rtotal=12+18
I=12/30
PR1=RI2
PR1=12*[tex]\frac{2}{5}[/tex]*[tex]\frac{2}{5}[/tex]
PR1=48/25

PR2=[tex]\frac{72}{25}[/tex]=2.88
Thanks!

There you go. Good job.
 

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