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A solution of hydrofluoric acid contains 2.0g of HF per litre and has a pH of 2.2. What is the dissociation constant for HF?

My Answer:

HF + H2O <-> H3O+ + F-

HF = 2.0g

H30+ = 10^-2.2 = .0063g

F- = H3O = .0063

Ka = [H3O+][F-] / HF

= (.0063)(.0063) / 2.0

=1.98 x 10^-5

Therefore the dissociation constant for HF is 2.0 x 10^-5

Can anyone tell me if I am on the right track?

Thanks

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# Homework Help: Dissociation Constant Homework Check

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