Distance and Time: Dimensions of a & b

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SUMMARY

The distance \( d \) that a particle moves is expressed as \( d = at + bt^2 \), where \( a \) and \( b \) are constants. To determine the dimensions of \( a \) and \( b \), one must consider the units of distance (meters) and time (seconds). The constant \( a \) represents acceleration, thus its dimensions are \( \text{m/s}^2 \), while \( b \) represents a coefficient related to time squared, yielding dimensions of \( \text{m/s}^2 \) as well, confirming that both constants share the same dimensional analysis.

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i need some help with this:

the distance d that a certain particle moves may be calculated from the expression d=at+bt^2, where a and b are constants; and T is the elapsed time. complete the following statement: the dimensions of the quantities a and b are..., respectively

help please i don't get it... thanks
 
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If d is in units of distance, e.g. meters, and time is in units of time, e.g. seconds (s), then if one were to equate d = v*t, v would have to be in units of velocity (speed), e.g. m/s,

distance = (distance/time) * time or distance (m) = velocity (m/s) * time (s). Units must be consistent.

Think about the units of acceleration.
 

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