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## Homework Statement

Given a crystal (cube) with regularly arranged atoms (Total 27 atoms)

The mass of each atom is 3.5*10^-25. The density of the crystal is 9.2*10^3

What is the shortest distance between the centres of two adjacent atoms?

## Homework Equations

density = mass / volume

## The Attempt at a Solution

Volume= (27*3.5*10^-25)/(9.2*10^3)=1.03*10^-27

Length(L)=1*10-9

Distance between two atoms is L/2=5.04*10^-10

Correct answer is 3.4*10^-9