Distance between sets (a triangle-type inequality)

  • Context: Graduate 
  • Thread starter Thread starter Identity
  • Start date Start date
  • Tags Tags
    Inequality Sets
Click For Summary
SUMMARY

The discussion focuses on the proof of the triangle-type inequality for distances between sets in the context of nonempty compact subsets of a metric space, denoted as \(\mathbb{H}(X)\). The key definitions include the distance from a point \(x \in X\) to a set \(B \in \mathbb{H}(X)\) as \(D_B(x) = \min\{d(x,b): b \in B\}\) and the distance from set \(A\) to set \(B\) as \(D_B(A) = \max\{D_B(a): a \in A\}\). The proof demonstrates that \(D_B(A) \leq D_B(C) + D_C(A)\) by establishing a relationship between the distances, ultimately showing that \(D_B(a) \leq \min_{c \in C} d(a,c) + S\), where \(S\) is defined as \(\max_{c \in C} \min_{b \in B} d(c,b)\).

PREREQUISITES
  • Understanding of metric spaces and compact subsets
  • Familiarity with distance functions and their properties
  • Knowledge of mathematical notation and proofs
  • Experience with concepts from topology, specifically related to sets
NEXT STEPS
  • Study the properties of nonempty compact subsets in metric spaces
  • Explore advanced topics in topology, focusing on distance functions
  • Learn about the implications of triangle inequalities in various mathematical contexts
  • Review proofs involving maximum and minimum functions in metric spaces
USEFUL FOR

Mathematicians, students of topology, and researchers interested in the properties of metric spaces and distance functions will benefit from this discussion.

Identity
Messages
151
Reaction score
0
I've been reading a book called Superfractals, and I'm having trouble with a particular proof:

Definitions:

The distance from a point [itex]x \in X[/itex] to a set [itex]B \in \mathbb{H}(X)[/itex] (where [itex]\mathbb{H}(X)[/itex] is the space of nonempty compact subsets of [itex]X[/itex] is:
[tex]D_B(x):=\mbox{min}\lbrace d(x,b):b \in B\rbrace[/tex]
The distance from [itex]A \in \mathbb{H}(X)[/itex] to [itex]B \in \mathbb{H}(X)[/itex] is:
[tex]D_B(A):=\mbox{max}\lbrace D_B(a):a \in A\rbrace[/tex]
for all [itex]A,B \in \mathbb{H}(X)[/itex].
The proof is to show that [itex]D_B(A) \leq D_B(C)+D_C(A)[/itex]. The proof goes:
[tex]\begin{array}{rcl}D_B(a) &=&\mbox{min}_{b \in B}d(a,b) \\<br /> &\leq& \mbox{min}_{b \in B}(d(a,c)+d(c,b))\\<br /> &=&d(a,c)+\mbox{min}_{b \in B}d(c,b)\\<br /> \end{array}[/tex]
Then
[tex]D_B(a) \leq \mbox{min}_{c \in C}d(a,c)+\mbox{max}_{c \in C}\mbox{min}_{b \in B}d(c,b)[/tex]

How do we reach this last step?
 
Physics news on Phys.org
Identity said:
I've been reading a book called Superfractals, and I'm having trouble with a particular proof:

Definitions:

The distance from a point [itex]x \in X[/itex] to a set [itex]B \in \mathbb{H}(X)[/itex] (where [itex]\mathbb{H}(X)[/itex] is the space of nonempty compact subsets of [itex]X[/itex] is:
[tex]D_B(x):=\mbox{min}\lbrace d(x,b):b \in B\rbrace[/tex]
The distance from [itex]A \in \mathbb{H}(X)[/itex] to [itex]B \in \mathbb{H}(X)[/itex] is:
[tex]D_B(A):=\mbox{max}\lbrace D_B(a):a \in A\rbrace[/tex]
for all [itex]A,B \in \mathbb{H}(X)[/itex].
The proof is to show that [itex]D_B(A) \leq D_B(C)+D_C(A)[/itex]. The proof goes:
[tex]\begin{array}{rcl}D_B(a) &=&\mbox{min}_{b \in B}d(a,b) \\<br /> &\leq& \mbox{min}_{b \in B}(d(a,c)+d(c,b))\\<br /> &=&d(a,c)+\mbox{min}_{b \in B}d(c,b)\\<br /> \end{array}[/tex]
Then
[tex]D_B(a) \leq \mbox{min}_{c \in C}d(a,c)+\mbox{max}_{c \in C}\mbox{min}_{b \in B}d(c,b)[/tex]

How do we reach this last step?

First of all, we notice that

[tex]\min_{b\in B}~d(c,b) \leq \max_{x\in C}~\min_{b\in B}~d(c,b)[/tex]

So

[tex]D_B(a)\leq d(a,c)+\mbox{min}_{b \in B}d(c,b)\leq d(a,c)+\mbox{max}_{c \in C}\mbox{min}_{b \in B}d(c,b)[/tex]

For notational issues, let [itex]S=\mbox{max}_{c \in C}\mbox{min}_{b \in B}d(c,b)[/itex] this is just a number.

So we have proven that

[tex]D_B(a)\leq d(a,c)+S[/tex]

But this holds for ALL c. So it must also hold for any particular c. So it must also hold for the c that minimizes d(a,c). So

[tex]D_B(a)\leq \min_{c\in C}~d(a,c)+S[/tex]
 
Thnks micromass :)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
3K
Replies
2
Views
2K