Libra_girl
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Homework Statement
A diverging lens of 6 mm focal length produces an image of magnification m = 1/2. What
is the distance between the object and the lens?
A diverging lens with a focal length of 6 mm produces an image with a magnification of m = 1/2. To find the distance between the object and the lens (do), two key equations are utilized: the magnification equation m = -di/do and the lens formula 1/do + 1/di = 1/f. By substituting the known values into these equations, one can solve for the object distance (do) effectively. The discussion emphasizes the importance of using both equations to find the relationship between the object distance and the image distance.
PREREQUISITESStudents studying optics, physics educators, and anyone interested in understanding the principles of lens behavior and image formation.
Libra_girl said:Homework Statement
A diverging lens of 6 mm focal length produces an image of magnification m = 1/2. What
is the distance between the object and the lens?
tiny-tim said:Hi Libra_girl ! Welcome to PF!
Hint: what equations do you know that relate the size of the object to the size of the image?![]()
Libra_girl said:Is it the equation: do/di = m or 1/do + 1/di = 1/f ?
tiny-tim said:Both equations!
Except isn't it m = -di/do?![]()
Libra_girl said:yeah it is sorry![]()
tiny-tim said:Both equations!
Except isn't it m = -di/do?![]()