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## Homework Statement

A diverging lens of 6 mm focal length produces an image of magnification m = 1/2. What

is the distance between the object and the lens?

- Thread starter Libra_girl
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- #1

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A diverging lens of 6 mm focal length produces an image of magnification m = 1/2. What

is the distance between the object and the lens?

- #2

tiny-tim

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Hi Libra_girl ! Welcome to PF!## Homework Statement

A diverging lens of 6 mm focal length produces an image of magnification m = 1/2. What

is the distance between the object and the lens?

Hint: what equations do you know that relate the size of the object to the size of the image?

- #3

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Hi Libra_girl ! Welcome to PF!

Hint: what equations do you know that relate the size of the object to the size of the image?

Is it the equation: do/di = m or 1/do + 1/di = 1/f ?

- #4

tiny-tim

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Is it the equation: do/di = m or 1/do + 1/di = 1/f ?

Except isn't it m = -di/do?

- #5

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Bothequations!

Except isn't it m = -di/do?

yeah it is sorry

Last edited:

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yeah it is sorry

Ok so I know f and I know m, now I am solving for do, but I don't know the di?Bothequations!

Except isn't it m = -di/do?

- #7

alphysicist

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You now have two equations in two unknowns. You can solve the magnification formula for one of the variables and plug it into the other formula. What does that give?

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