1. The problem statement, all variables and given/known data An object is dropped from the roof. A second object is dropped 1.50 s later. How far apart are the objects when the second one has reached a speed of 12.0 m/s. GIVEN Obj 1 - vi=0 m/s , a=-9.8 m/s/s Obj 2 - vi=0 m/s, vf=12.0 m/s, a=-9.8 m/s/s 2. Relevant equations d=vf*t+1/2*a*t2 3. The attempt at a solution d=12.0*1.50+1/2*-9.8*2.25 d=18-11.025 d=6.975 I'm not sure exactly how to do this when there's two objects :S. The answer is 29.0 m, but I want to understand how to get it.