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Homework Statement
An object is dropped from the roof. A second object is dropped 1.50 s later. How far apart are the objects when the second one has reached a speed of 12.0 m/s.
GIVEN
Obj 1 - vi=0 m/s , a=-9.8 m/s/s
Obj 2 - vi=0 m/s, vf=12.0 m/s, a=-9.8 m/s/s
Homework Equations
d=vf*t+1/2*a*t2
The Attempt at a Solution
d=12.0*1.50+1/2*-9.8*2.25
d=18-11.025
d=6.975
I'm not sure exactly how to do this when there's two objects :S.
The answer is 29.0 m, but I want to understand how to get it.