(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An object is dropped from the roof. A second object is dropped 1.50 s later. How far apart are the objects when the second one has reached a speed of 12.0 m/s.

GIVEN

Obj 1 - vi=0 m/s , a=-9.8 m/s/s

Obj 2 - vi=0 m/s, vf=12.0 m/s, a=-9.8 m/s/s

2. Relevant equations

d=vf*t+1/2*a*t2

3. The attempt at a solution

d=12.0*1.50+1/2*-9.8*2.25

d=18-11.025

d=6.975

I'm not sure exactly how to do this when there's two objects :S.

The answer is 29.0 m, but I want to understand how to get it.

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# Homework Help: Distance between two objects dropped at different times

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