Calculating Force from Stopping in Gravity: Help Appreciated

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SUMMARY

The discussion centers on calculating the force required to stop an object falling towards Earth at a velocity of 0.6 m/s. The user initially applies the formula a = (vf - vi) / t with vi as 0.6 m/s, vf as 0, and t as 0.1 s, leading to an acceleration calculation. The net force is determined using f = ma, where m is 150 kg. The moderator clarifies that the net force includes gravitational force, prompting the need for a comprehensive understanding of all forces acting on the object.

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Pete78
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Hi
I am trying to roughly calculate a force.
If i am moving an object towards the Earth and then stop it, how much force will this generate?
a=vf-vi/t
- vi =0.6m/s
-vf= 0
-t = 0.1 s

This equalling - a

Then applying f=ma
m=150kg

Im unsure how to add gravity into this.

would...
0-(9.8+0.6)/0.1 be a good way to estimate this?

Any help is appreciated.
Thanks in advance[Moderator's note: Moved from a technical forum and thus no template.]
 
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No. The units of grand v are not the same anyway.
Presumably the object is freely falling and you apply an upward force to stop it when it reaches a speed of 0.6 m/s. You want to know that force.
In your equation f = ma, f is actually the net force and consists of more than one force acting on it. Can you identify these forces?
 

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