- #1

Jeff97

- 92

- 5

- Homework Statement
- I'm asked to calculate a stone being dropped from rest to hit the water it takes 2.7s.

Now they throw the stone and it takes only 2.3s to reach the water what's was the speed they threw it at?

- Relevant Equations
- Vf=Vi+at d = 0.5 * g * t2

What I know for Number 1. t=2.7s d=? Vi=0m/s^-1 a=9.8m/s^-2 Vf=? Equation to use? Vf=Vi+at= 0+9.8m/s^-2x2.3= 26.46m/s So for number one the final velocity is 26.46m/s

Number 2 I know t=2.3s d=35.721 vi? Vf? a=9.8? what formula do I use?

**d = 0.5 * g * t2 = 0.5x9.8x2.7^2=35.721**Number 2 I know t=2.3s d=35.721 vi? Vf? a=9.8? what formula do I use?

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