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Distance covered by a moving object versus friction in an inclined plane

  1. Sep 24, 2009 #1
    1. The problem statement, all variables and given/known data
    A 5 kg object is pushed up along a plane inclined 30 degrees from the horizontal by a force of 20.25 N. If the velocity is 2.0 m/s at the foot of the plane and the coefficient of kinetic friction between the plane and the object is 0.25, how far up the plane will the object go?

    2. Relevant equations
    f = uN

    3. The attempt at a solution
    f = uN
    f = (0.25)(20.25 N)
    f = 5.0625 N

    I really don't know how to continue the solution. Do I need to use trigonometry here? I think gravity will cause the moving object to decelerate and stop at some point when it goes up. I just don't know what formulas and equations to use before I can arrive at the solution. Thanks in advance.
  2. jcsd
  3. Sep 24, 2009 #2


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    Homework Helper

    20.25 N is not the normal reaction. It is the force applied to the object. Mass is given. Find the acceleration along the plane.
    What is the component of mg perpendicular to the plane?
    What is the component of mg parallel to the plane?
    What is the magnitude and the direction of the frictional force?
    What is the net acceleration up the plane?
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