Distance from points to plane using normal vector

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Damascus Road
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I have two points, P(0,0,0) and Q(-1,-2,0)

and a plane x + 7y - 15z = 30

May I simply:

[tex]\sqrt{(1-0)^{2} + (7-0)^{2} + (-15-0)^{2}}[/tex]

[tex]\sqrt{(1+1)^{2} + (7+2)^{2} + (15-0)^{2}}[/tex]

and the one with the lesser magnitude is closer?
 
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